Physics 225, Fall 2003 Final Exam (Section 1)
Dr. Shapiro
Closed book – two 3"×5" note cards and the handouts may be used. Please do not write on either the test or the handout. Both must be turned in with your test answers. Partial Credit will be given. Please write clearly and show all your work (answers without supporting work will not receive credit).
Problem #1) The oscillator shown below consists of a block attached to a spring. The mass of the block is 0.25kg, and the surface is frictionless. At t = 0 s, the block is displaced 0.1m and released. The period of the motion is measured and found to be 0.4 s. (a) What is the angular frequency of the motion? (b) What is the spring constant? (c) At t = 0.1 s what is velocity of the block? (d) At t = 0.1 s what is the acceleration of the block?

(a)
and
so 
(b) From
we have 
(c) From
we see that 
(d) From
we have 
Problem #2) The horizontal bar in the diagram below is rigid and uniform and has a mass of 2.0 kg. It is 1.5 m in length, and it is attached to the wall with a hinge. A cord that is attached to the midpoint of the bar and to the wall makes a 45 deg angle with the bar. A 5 kg mass is suspended from the far end of the bar. (a) Find the tension in the cord. (b) Find the horizontal force from the wall on the bar. (c) Find the vertical force from the wall on the bar.
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(a)
Balancing torques (using the hinge as the axis of rotation) we have
so T =
166.3N.
(b)
Balancing forces in the x-direction, we have
so Fhx
= 117.6 N.
(c)
Balancing forces in the y-direction, we have
so Fky
= -49.0 N.
Problem
#3) A
uniform solid ball rolls smoothly without slipping along a floor, then
up a 15
deg ramp. The ball stops momentarily
when it has rolled 1.25 m along the ramp.
What was the initial velocity of the center of mass of the ball?
(Hint: use energy conservation, and note
that for a solid ball
.)
When the
ball has traveled 1.25 m along the ramp, it has risen
so it
must have had a total energy of
. Equating this to
the initial kinetic energy, we have
where we have taken
advantage of the fact that
for an object that
rolls without slipping. So 
Problem #4) A 5 g bullet moving directly upward at 500 m/s hits a 5 kg block of wood. The bullet stops in the block. (a) What is the kinetic energy of the bullet just before the collision? (b) What is the momentum of the bullet just before the collision? (c) What is the momentum of the block (with the bullet embedded in it) just after the collision? (d) How much energy was lost in the collision? (e) How high does the block rise above its initial position?

(a) Let m
represent the mass of the bullet and M represent the mass of
the
block. Then
.
(b) 
(c) Since momentum is conserved in the collision this also is the momentum of the block (with bullet imbedded) just after the collision. Let’s call it P.
(d)The
energy just after the collision is
so nearly all the
energy of the bullet is lost – 624.4 J to be exact.
(e) The
block will rise until all of its kinetic energy has been converted to
gravitational potential energy, so
which implies that h
= 0.012 m or 1.2 cm.
Problem #5) A 20 kg body is moving in the positive x direction with a speed of 200 m/s when, owing to an internal explosion, it breaks into three parts. One part, with a mass of 10 kg moves away from the point of explosion with a speed of 100 m/s in the positive y direction. A second fragment, with a mass of 4 kg, moves in the negative x direction with a speed of 500 m/s. (a) What is the x component of the velocity of the third (6 kg) fragment? (b) What is the y component of the velocity of the third (6 kg) fragment? (c) What is the minimum amount of energy that was released in the explosion? (Hints: momentum must be conserved in both the x and y directions, and you can ignore all frictional and gravitational effects.)
(a) Before
the explosion all the momentum was in the x-direction and
. Since the momentum
in the x-direction is conserved, after the explosion we have
where v3x
is the x-component of the third fragment’s total
velocity. Solving, we find
.
(b) Before
the explosion there was no momentum in the y-direction, so
. Solving, we find
.
(c) The
kinetic energy before the explosion was
. The total kinetic
energy after the explosion is
so a minimum of
had to be released in the explosion.
Problem
#6) In the
diagram shown below a cord is looped over a pulley, which can be
treated as a
solid cylinder. The pulley has a mass
of 0.25 kg and a radius of 0.05 m. A
1.0 kg mass is attached to the left end of the cord, and a 1.5 kg mass
is
attached to the right end of the cord.
Assume that the axle of the pulley is frictionless and that the cord
does not slip. Initially the two masses
are held in place, then they are released.
(a) After the masses are released, what is the torque on the
pulley? (b) What is the angular
acceleration of the pulley? (c) What is
the linear acceleration of each mass?
(Note that
for a solid
cylinder. Hint: the tension on the left
is not the same as the tension on the right.)
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Let T1 be the tension on the left, and T2 the tension on the right. Then
and since
must be negative (the pulley turns clockwise).
Then![]()
where the – sign is needed since the
acceleration obviously
upward for the mass on the left. And,
where we have taken
advantage of the fact that the linear acceleration of the masses is
numerically
equal to the tangential acceleration of the pulley. Solving for
the tensions, and inserting in the first equation we
have
where M is the
mass of the pulley. Solving for the
angular acceleration we have
. Then,
(a)
.
(b)
.
(c)
in magnitude. The acceleration is
positive for the 1 kg
mass and negative for the 1.5 kg mass according to our usual
conventions.
Problem #7) A railroad car moves at a constant speed of 4.0 m/s under a grain elevator. Grain drops into it at the rate of 500 kg/min. What is the magnitude of the force needed to keep the car moving at constant speed if friction is negligible?
since the velocity of
the car is constant.
Problem #8) A 0.06 kg rubber ball is thrown vertically downward hitting a cement floor with a velocity of 10 m/s. The ball is in contact with the floor for 0.015 s, and it rebounds with an initial velocity of 7.5 m/s. (a) What average force did the ball exert on the floor while it was in contact? (b) How high does the ball rise above the floor after it rebounds?
(a) From
the impulse-momentum theorem we have
, so since the motion is entirely in the y-direction
.
(b)
Equating the kinetic energy just after rebound with the gravitational
potential
energy at the maximum height, we have
so
.